#!/usr/bin/python3
"""
Given a binary matrix A, we want to flip the image horizontally, then invert it
, and return the resulting image.

To flip an image horizontally means that each row of the image is reversed.
For example, flipping [1, 1, 0] horizontally results in [0, 1, 1].

To invert an image means that each 0 is replaced by 1, and each 1 is replaced by
0. For example, inverting [0, 1, 1] results in [1, 0, 0].

Example 1:

Input: [[1,1,0],[1,0,1],[0,0,0]]
Output: [[1,0,0],[0,1,0],[1,1,1]]
Explanation: First reverse each row: [[0,1,1],[1,0,1],[0,0,0]].
Then, invert the image: [[1,0,0],[0,1,0],[1,1,1]]
Example 2:

Input: [[1,1,0,0],[1,0,0,1],[0,1,1,1],[1,0,1,0]]
Output: [[1,1,0,0],[0,1,1,0],[0,0,0,1],[1,0,1,0]]
Explanation: First reverse each row: [[0,0,1,1],[1,0,0,1],[1,1,1,0],[0,1,0,1]].
Then invert the image: [[1,1,0,0],[0,1,1,0],[0,0,0,1],[1,0,1,0]]
Notes:

1 <= A.length = A[0].length <= 20
0 <= A[i][j] <= 1
"""
from typing import List


class Solution:
    def flipAndInvertImage(self, A: List[List[int]]) -> List[List[int]]:
        """
        one pass
        """
        for row in A:
            prev = list(row)
            for i in range(len(row)):
                row[i] = prev[-1-i] ^ 1

        return A
